1.

11.2 g carbon reacts completely with 19.63 litre O_(2) at NTP. The cooled gases are pased through 2 litre of 2.5 N NaOH solution. Calculate concentration of remaining NaOH and Na_(2)CO_(3) in solution. (CO does not react with NaOH under these conditions.)

Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of carbon be converted into CO and y moles of carbon be converted into `CO_(2)`. <br/> `underset(x)(C )+(1)/(2)underset(x//2)(O_(2)) to CO` <br/> `underset(y)C+underset(y)(O_(2)) to CO_(2)` <br/> Total <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of oxygen used `=(x)/(2)xx22.4+yxx22.4` <br/> =19.63 <br/> 11.2x+22.4y=19.63 <br/> `x+y=(11.2)/(12)`, i.e., 12x+12y=11.2 <br/> Solving eqs. (i) and (ii), we get <br/> x=0.11, y=0.82 <br/> Number of moles of `CO_(2)` formed =0.82 <br/> Number of milliequivalents of <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> solution through which `CO_(2)` is massed `=NxxV=2.5xx2000=5000` <br/> Number of milliequivalents of `CO_(2)` passed`=0.82xx2xx1000` <br/> =1640 <br/> `2NaOH+CO_(2) to Na_(2)CO_(3)+H_(2)O` <br/> Number of milliequivalents of `Na_(2)CO_(3)=1640` <br/> `N_(Na_(2)CO_(3))=(1640)/(2000)=0.82` <br/> Number of milliequivalents of remaining NaOH <br/> =5000-1640=3360 <br/> Normality of remaining `NaOH=(3360)/(2000)=1.68`</body></html>


Discussion

No Comment Found

Related InterviewSolutions