1.

._(11)^(23)Na is the most stable isotope of Na. Find the process by which._(11)^(24) Na can undergo radioactive decay :

Answer»

`._(11)Na^(23)`
`._(10)NE^(22)`
`._(9)F^(18)`
`_(12)Mg^(22)`

Solution :`[._(11)Na^(23)` stable isotope i. e. `._(11)Na ^(22) ` has n/p ratio lesser than REQUIRED To increase n/p ratio
`{:(._(11)Na ^(22),rarr,._(10)Ne^(22),+,._(1)e^(0)),(,,,,("positron emission")):}`
Or
`{:(._(-1)e^(0),+,._(11)Na^(22),rarr,._(10)Ne^(22)),(("k-electron caputre"),,,,):}`


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