11. Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass ofAl = 27 u)

11. Calculate the number of aluminium ions present in 0.051 g of alumi

1.	11. Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass ofAl = 27 u)
Answer» Aluminium OXIDE = Al2O3in 1 molecule there are 2 Al+3 ionsMolecular weight of Aluminium oxide = 2(27)+3(16)=54+48=102ghence, 102g molecule contain 54g Al+3and 0.051g will contain, 54/102 ×0.051 =0.027g Al+3 ions.Please mark as BRAINLIEST and follow if it helped you!