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11 grams of a gas occupy 5.6 liters of volume at STP the gas is |
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Answer» At STP = 1 mole of substanceoccupies 22.4L of volume. THEREFORE for the above gas to acquire 22.4 Lvolume its MASS should be 22.4/5.6 x11 = 44g = molar mass of gasExplanation:ACHHA sholiabb mann jao NA |
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