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11.If α and β are the zeroes of the quadratic polynomial p(s)-3s^2-6s+ 4, then the value of \frac{\alpha}{\beta}+\frac{\beta}{\alpha}+2\left(\frac{1}{\alpha}+\frac{1}{\beta}\right)+3 \alpha \beta(A) 6(B) 8(C) 5(D) 4

Answer»

alpha + beeta = -(b/a)

alpha + beeta = -(b/a)



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