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11. What volume of propane is burnt for every 500 cm3 ofair used in the reaction under the same conditions?(Assuming oxygen is 1/5th of air)C3H8 + 50,- 3CO, + 4H20(2017)

Answer»

C3H8 + 5 O2 ----> 3 CO2

propane = 1v , oxygen = 5v therefore volume of propane required = 100 cm3



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