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112% labelled oleum is diluted with sufficient water. The solution on mixing with 5.3xx102gm Na_(2)CO_(3) liberates CO_(2). The volume of Co_(2) given out at 1 atm at 273 K will be |
Answer» <html><body><p>1.12 lit<br/>1.23 lit<br/>2.2 lit <br/>25.5 lit</p>Solution :Final weight of `H_(2)SO_(4)=<a href="https://interviewquestions.tuteehub.com/tag/112-268456" style="font-weight:bold;" target="_blank" title="Click to know more about 112">112</a>` gms <br/> `Na_(2)O_(3)+H_(2)SO_(4)rarrNa_(2)SO_(4)+H_(2)O+CO_(2)` <br/> 530 <a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a> 112 gm <br/> = 5 <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> 1.14 moles <br/> <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of `CO_(2)=1.14xx22.4=25.5` lit.</body></html> | |