12.15 g of magnesium gives 20.20 g of magnesium oxide on burning. The

1.	12.15 g of magnesium gives 20.20 g of magnesium oxide on burning. The actual mass of magnesium oxide that should be produced is 20.15 g. Calculate absolute error and relative error.
Answer» The observed value is 20.20 g and accepted (true) value is 20.15 g. i. Absolute error = Observed value – True value = 20.20 – 20.15 = 0.05 g ii. Relative error = \(\frac{Absolute\,error}{True\,value}\) x 100% = \(\frac{0.05}{20.15}\) x 100% = 0.25% ∴ i. Absolute error = 0.05 g ii. Relative error = 0.25 %

12.15 g of magnesium gives 20.20 g of magnesium oxide on burning. The actual mass of magnesium oxide that should be produced is 20.15 g. Calculate absolute error and relative error.

Answer»

The observed value is 20.20 g and accepted (true) value is 20.15 g.

i. Absolute error = Observed value – True value

= 20.20 – 20.15

= 0.05 g

ii. Relative error = \(\frac{Absolute\,error}{True\,value}\) x 100%

= \(\frac{0.05}{20.15}\) x 100%

= 0.25%

∴ i. Absolute error = 0.05 g

ii. Relative error = 0.25 %