12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M CrSO_(4) which is oxidised Cr(SO_(4))_(3) To what oxidation state is the selenium converted during the reaction ?

12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M

1.	12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M CrSO_(4) which is oxidised Cr(SO_(4))_(3) To what oxidation state is the selenium converted during the reaction ?
Answer» <html><body><p></p>Solution :Let O.N of se in the new compound =<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C08_E17_017_S01.png" width="80%"/> <br/> Now 12.53 `cm^(3)` of 0.051 M `SeO_(2)=12.53xx0.51=0.63` millimoles of `SeO_(2)` <br/> and 25.5 `cm^(3)` of 0.1 M `CrSO_(4)=25.5xx0.1=2.55` millimole of `CrSO_(2)` <br/>But according to balancedredox equation (4-x) moles of `CrSO_(4)` <a href="https://interviewquestions.tuteehub.com/tag/reduce-1181332" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCE">REDUCE</a> 1 mole of `SeO_(2)` <br/> `therefore2.55` millimoles of `CrSO_(4)` it reduce `SeO_(2)=(2.55)/(4-x)` millimoles <br/> But `SeO_(2)` actually <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a>= 0.64 millimoles <br/> Equating these two values we have`(2.55)/(4-x)=0.64 or x=0`</body></html>