12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M CrSO_(4) which is oxidised Cr(SO_(4))_(3) To what oxidation state is the selenium converted during the reaction ?

12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M

1.	12.53 cm^(3)of 0.51 M SeO_(2) reacts exactly with 25.5 cm^(3) of 0.1 M CrSO_(4) which is oxidised Cr(SO_(4))_(3) To what oxidation state is the selenium converted during the reaction ?
Answer» Solution :Let O.N of se in the new compound =X Now 12.53 `cm^(3)` of 0.051 M `SeO_(2)=12.53xx0.51=0.63` millimoles of `SeO_(2)` and 25.5 `cm^(3)` of 0.1 M `CrSO_(4)=25.5xx0.1=2.55` millimole of `CrSO_(2)` But according to balancedredox equation (4-x) moles of `CrSO_(4)` REDUCE 1 mole of `SeO_(2)` `therefore2.55` millimoles of `CrSO_(4)` it reduce `SeO_(2)=(2.55)/(4-x)` millimoles But `SeO_(2)` actually REDUCED= 0.64 millimoles Equating these two values we have`(2.55)/(4-x)=0.64 or x=0`