1,2-Dibromopropane on treatment with X moles of NaNH_2 followed by treatment with ethyl bromide gave a pentyne. The value of X is

1,2-Dibromopropane on treatment with X moles of NaNH_2 followed by tre

1.	1,2-Dibromopropane on treatment with X moles of NaNH_2 followed by treatment with ethyl bromide gave a pentyne. The value of X is
Answer» One<BR>Two THREE Four Solution :i) `CH_3CHBr - CH_2Br + 2NaNH_2 to CH_3C -= CH + 2NaBr + 2NH_3` II) `CH_3 C -= CH + NaNH_2 to CH_3C -= C^(-) Na^(+) + NH_3` iii) `CH_3C -= C^(-) Na^(+) + CH_3CH_2 Br to CH_3C -= C CH_2 CH_3 + NaBr` Thus 3 MOLE of `NaNH_2` is used .