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12 g of Mg (at. Mass 24) will react completely with acid to giveA. One mole of `H_(2)`B. `1//2` mole of `H_(2)`C. `2//3` mole of `O_(2)`D. Both `1//2` mol of `H_(2)` and `1//2` mol of `O_(2)` |
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Answer» Correct Answer - B `Mg^(+2) equiv H_(2)` `n=(12 gm)/(24 gm)=1/2` mole of `H_(2)` |
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