1.

12 guests at a dinner party are to be seated along a circular table. Supposing that the master and mistress of the house have fixed seats opposite to one another and that there are two specified guests who must always be placed next to one another. The number of ways in which the company can be placed, is

Answer» combinations that can be made on right side and left side=`5 & 5`
total combinations to be made`10`
if X,Y are the persons , the combination XY & YX can also be possible
no of possibilities will be = `2*(5*2)*10! = 20*10!`
option 1 correct.


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