1.

-12*u %2B 3*u^3 - 4*u^2 %2B 16

Answer»

Let p(u) =3u³-4u²-12u+16Factors of 16 are 1,2,4,8,16On checking we getP(2)=24-16-24+10=0So u-2 is the one factorNow3u³-6u²+2u²-4u-8u+163u²(u-2)+2u(u-2)-8(u-2)(u-2)(3u²+2u-8)(u-2)(3u²+6u-4u-8)(u-2){3u(u+2)-4(u+2)}(u-2)(u+2)(3u-4)

(u-2)(u+2)(3u-4) is the correct answer of the given question

(u-2)(u+2)(3u-4) is the correct answer



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