120 g Mg was burnt in air to give a mixture of MgO and Mg_(3)N_(2). The mixture is now dissolved in HCl to form MgCl_(2) and NH_(4)Cl, if 107 gram NH_(4)Cl is produced. Then the moles of MgCl_(2) formed is: Mg + (1/2)O_(2) rightarrow MgO...........................(i) 3Mg + N_(2) rightarrow Mg_(3)N_(2) .............................(ii) MgO + 2HCl rightarrow MgCl_(2) + H_(2)O ..........................(iii) Mg_(3)N_(2) + 8HCl rightarrow 2NH_(4)Cl + 3MgCl_(2).......................(iv)

120 g Mg was burnt in air to give a mixture of MgO and Mg_(3)N_(2). Th

1.	120 g Mg was burnt in air to give a mixture of MgO and Mg_(3)N_(2). The mixture is now dissolved in HCl to form MgCl_(2) and NH_(4)Cl, if 107 gram NH_(4)Cl is produced. Then the moles of MgCl_(2) formed is: Mg + (1/2)O_(2) rightarrow MgO...........................(i) 3Mg + N_(2) rightarrow Mg_(3)N_(2) .............................(ii) MgO + 2HCl rightarrow MgCl_(2) + H_(2)O ..........................(iii) Mg_(3)N_(2) + 8HCl rightarrow 2NH_(4)Cl + 3MgCl_(2).......................(iv)
Answer» 3 MOLES 6 moles 5 moles 10 moles Answer :C