

InterviewSolution
Saved Bookmarks
1. |
120g of urea is present in 5L of solution, the active mass of urea isA. 0.2B. 0.06C. 0.4D. 0.88 |
Answer» Correct Answer - C Active mass = concentration = M ` :. M=W_(2)/(M_(2) xx V (L))=120/(60 xx 5)=12/30=0.4` |
|