1.

120g of urea is present in 5L of solution, the active mass of urea isA. 0.2B. 0.06C. 0.4D. 0.88

Answer» Correct Answer - C
Active mass = concentration = M
` :. M=W_(2)/(M_(2) xx V (L))=120/(60 xx 5)=12/30=0.4`


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