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125 drops of water each of radius `2 mm` and carrying charge of `1 nC` are made to form a bigger drop. Find the capacitance and potential of the bigger drop. |
Answer» Correct Answer - `1.1 pF ; 113.6 V` Let `r` and `R` radii of small and bigger drop respectively. Volume of bigger drop `= 1.25xx` volume of small drop `(4)/(3) pi r^(3) = 125xx(4)/(3) pi r^(3)` `R = 5 r = 5xx2xx10^(-3) = 10xx10^(-3)m` Capacitance fo bigger drop `C = 4pi in_(0) R = (10xx10^(-3))/(9xx10^(9)) = 1.1 pF` Charge on bigger drop, `q = 125xx10^(-9)C` `:.` Potential of bigger drop `V = (q)/(C) = (125xx10^(-9))/(1.1xx10^(-12)) = 113.6 V` |
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