125. The taxi fare in a city is as follows: For the first kilometre, t

1.	125. The taxi fare in a city is as follows: For the first kilometre, the fare is Rs.8 and for thesubsequent distance it is Rs.5 per km. Taking the distance covered as x km and totalfare as Rs. y, write a linear equation for this information, and draw its graph.
Answer» Given,Total distance covered= xkm=1+(x-1)km Fare For first kilometre= ₹8 Fare for subsequent distance= ₹5 per km Fare for next(x-1)km= 5(x-1) A.T.Q Total fare= y 8+5(x-1)=y 8+5x-5=y 5x-y+3=0 Which is the required linear equation. It can also be written as y= 5x+3 When X = 0 ,then Y = 3,When x=1, then y=5+3=8 When x= 2, then y= 10+3=13

125. The taxi fare in a city is as follows: For the first kilometre, the fare is Rs.8 and for thesubsequent distance it is Rs.5 per km. Taking the distance covered as x km and totalfare as Rs. y, write a linear equation for this information, and draw its graph.

Answer»

Given,Total distance covered= xkm=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y=5+3=8

When x= 2, then y= 10+3=13