12g M2O3 contains 8g of metal. Atomic mass of metal is :(a) 12(b) 2

1.	12g M2O3 contains 8g of metal. Atomic mass of metal is :(a) 12(b) 24(c) 36(d) 48
Answer» Correct option is 4. 48 Given: 12gM₂O₃ contains 8g of metal. To find: We have find the atomic mass of the metal. Solution: Atomic mass of oxygen = 16 Here three oxygen atoms are present so, total atomic mass = 16 x 3 = 48 12gM₂O₃ contains 8g of metal. The amount of oxygen is = (12 - 8) = 4g Now, 4g of oxygen has total atomic mass 48g 8g of metal has total atomic mass = \(\frac{8\times 48}4\) = 96 Atomic mass of the metal can be given as- = \(\frac{96}{2}\) = 48 Atomic mass of metal is 48.

12g M2O3 contains 8g of metal. Atomic mass of metal is :(a) 12(b) 24(c) 36(d) 48

Answer»

Correct option is 4. 48

Given: 12gM₂O₃ contains 8g of metal.

To find: We have find the atomic mass of the metal.

Solution:

Atomic mass of oxygen = 16

Here three oxygen atoms are present so, total atomic mass = 16 x 3 = 48

12gM₂O₃ contains 8g of metal.

The amount of oxygen is = (12 - 8) = 4g

Now, 4g of oxygen has total atomic mass 48g

8g of metal has total atomic mass = \(\frac{8\times 48}4\) = 96

Atomic mass of the metal can be given as-

= \(\frac{96}{2}\)

= 48

Atomic mass of metal is 48.

Discussion

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