13. The equivalent weight of MnCl2 is half of itsmolecular weight when

1.	13. The equivalent weight of MnCl2 is half of itsmolecular weight when it is converted to
Answer» net oxidation state of Mn in MnCl2 is Mn+(Cl2)=0 so,Mn+(-1)2=0 (net charge of Cl=-1 Mn=2 now net charge of Mn in MnO2= Mn+(-2)2 (net charge on O=-2 Mn=4 MnCl2-----MnO2 equivalent weight =molecular weight (let M)/change in the oxidation state equivalent weight=M/(4-2) =M/2 Thus equivalent weight of MnCl2 is half the molecular weight when it is converted to MnO2

13. The equivalent weight of MnCl2 is half of itsmolecular weight when it is converted to

Answer»

net oxidation state of Mn in MnCl2 is Mn+(Cl2)=0

so,Mn+(-1)2=0 (net charge of Cl=-1

Mn=2

now net charge of Mn in MnO2=

Mn+(-2)2 (net charge on O=-2

Mn=4

MnCl2-----MnO2

equivalent weight =molecular weight (let M)/change in the oxidation state

equivalent weight=M/(4-2)

=M/2

Thus equivalent weight of MnCl2 is half the molecular weight when it is converted to MnO2