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132).Fig. 15.110a triangular field are 15 m, 16 m and 17 m. With the three corners of the fieldowa ind the area of the field which cannot be grazed by three animalsSies buffalo and a horse are tied separately with ropes of length7 m each to graze inINCERT EXEMPLARIANSWERS |
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Answer» Solution:- Let ABC be the triangular field with sides Ac = 15 m, AB = 16 m and BC = 17 mAnd,Let the place where the cow, the buffalo and thehorse are tied, are three sectors i.e. sector ADE, sector BFG and sector CHIThe area of triangular field by Heron's formula =√s(s-a)(s-b)(s-c)s = (a+b+c)/2s = (15+16+17)/2s = 48/2s = 24 m√24(24-15)(24-16)(24-17)√24*9*8*7√12096Area of triangular field = 109.98 sq mArea of the grazed part = Area of the triangular field = Area of the sector ADE + Area of sector BFG + Area of sector CHI= π*7²*∠A/360 + π*7²*∠B/360 +π*7²*∠C/360=π*7²(∠ A + ∠ B + ∠ C)/360= 22/7*7*7*180/360= 154/2Area of the grazed part = 77 sq mNow, the area of the field which cannot be grazed by these animals= 109.98 - 77= 32.98 sq m |
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