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InterviewSolution
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14. Sum of the areas of two squares is 468m2. If the difference of their perimetersis24m,find the sides of the two squareshroiden work in 4 davs, while 3 women and |
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Answer» Let the side of the larger square be x.Let the side of the smaller square be y.According to the question, x2 + y2 = 468 --------- (1)Perimeters of the squares = 4x and 4y.⇒ 4x - 4y = 24⇒ x– y = 6⇒ x= 6 + yx^2 + y^2 = 468Substituting the value of x in equation (1)⇒ (6+y)^2 + y^2 = 468⇒ 2y^2 + 12y + 36 = 468⇒ y^2 + 6y + 18 = 234⇒ y^2 + 6y - 216 = 0⇒ (y – 12)(y + 18) = 0⇒ y = 12 or -18Since y denotes a length, it cannot be negative.∴ y = 12⇒ x = (12 + 6) = 18 m ∴ Sides of the squares are 18 m and 12 m. |
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