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15. A man is 4 times as old as his son. After 16 years he will be only twice as old as his son.Find their present ages. |
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Answer» Let the present age of father be x and the son be y.Now, x = 4y ---------- (1)After 16 years, age of father will be x+ 16age of son will be y +16Therefore, x + 16 = 2( y + 16) x + 16 = 2y + 32x = 2y + 16or 4y = 2y + 16 {Using equation (a)}2y = 16y = 8Plugging back the value of y in equation (1), we get:x = 4*8 = 32Hence, the present age of father is 32 years and present age of son is 8 years. |
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