Saved Bookmarks
| 1. |
15 g of ammonium chloride is dissolved in 250 ml of solution? Calculate the mass by volume percentage of solution |
|
Answer» Calculate the amount of ammonium chloride required to dissolve in 500mL ... Mass in g=0.9 ×53.5=48.15g ... Get Instant Solutions, 24x7.Calculate the amount of ammonium chloride required to dissolve in 500mL water to have pH=4.5 (K b for NH 4 OH is 1.8×10 −5 )[H + ]=10 −pH =10 −5 =3.162×10 −5 MLet C be the CONCENTRATION of NH 4 CL NH 4+ +H 2 O⇌NH 4 OH+H + C(1−h) Ch ChIf h is small thenK h =Ch 2 [K h = K a K w = 1.8×10 −5 10 −14 =5.5×10 −10 ]h= ChK h = [H + ]K h = 3.162×10 −5 5.5×10 −10 =1.739×10 −5 C= h[H + ] = 1.739×10 −5 3.162×10 −5 =1.8molL −1 500mL of water contains= 21.8 =0.9molMass in g=0.9×53.5=48.15gThe pKa of CH3COOH and pKb of NH4 OH is 4.76 and 4.75. RESPECTIVELY. Calculate the hydrolysis constant of ammonium ACETATE (CH3 COONH4 ) at 298 K and also the degree of hydrolysis and pH of itsCalculate the pH of 1.0×10 −3 M sodium phenolate, NaOC 6 H 5 . K a for HOC 6 H 5 is 1.05×10 −10 |
|