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150 mL of `C_(2)H_(5)OH`(density = 0.78 g `mL^(-1)`is diluted to one litre by adding water, molality of the solution isA. 2.54B. 11.7C. 2.99D. 29.9 |
Answer» Correct Answer - C `m=(W_(2) xx 1000)/(M_(2) xx W_(1)(g))` 150 mL `C_(2)H_(5) OH=150 xx 0.78 g =117.0 g=W_(2)` Water =850 g = `W_(2)`=46 g `"mol"^(-1) `"Molality"= `(117 xx 1000)/ (46 xx 850)=2.99` |
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