16. 0.16g of dibasic acid requires 25 mlneutralisation. The molecular

1.	16. 0.16g of dibasic acid requires 25 mlneutralisation. The molecular mass of theacid is1. 2563. 322. 644. 128
Answer» At neutralisation, 25 ml N/10 NaOH≡25 ml N/10 acid Now, 25 ml N/10 acid = 0.16 gm So, 1000 ml N/10 acid = (0.16/25) x 1000 = 6.4 g Therefore, 1000 ml N acid = 6.4 x 10 = 64 g Thus, the equivalent weight of acid = 64 g Since the acid is dibasic, The molecular weight of acid = 64 x 2 = 128 g

16. 0.16g of dibasic acid requires 25 mlneutralisation. The molecular mass of theacid is1. 2563. 322. 644. 128

Answer»

At neutralisation,

25 ml N/10 NaOH≡25 ml N/10 acid

Now,

25 ml N/10 acid = 0.16 gm

So,

1000 ml N/10 acid = (0.16/25) x 1000

= 6.4 g

Therefore,

1000 ml N acid = 6.4 x 10 = 64 g

Thus, the equivalent weight of acid = 64 g

Since the acid is dibasic,

The molecular weight of acid

= 64 x 2 = 128 g