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InterviewSolution
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16.8g NaHco3 is treated with 12.0 g CH3CooH the residue was found to weight 20 t . determine the mass of co2 escaped in the reaction |
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Answer» The mass of residue, is CH 3 COONA solution, should be 24G of CH 3 COONa solution.In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium ACETATE, carbon dioxide and waterNaHCO 3 +CH 3 COOH⟶CH 3 COONa+CO 2 +H 2 OAccording to law of conversation of masses,TOTAL masses of reactants = total masses of productsreactants are 8.4g NaHCO 3 and 20g CH 3 COOH.total mass of reactants is =28.4gmass of residue = (28.4g reactants mass) − (4.4g CO 2 ) = 24.0g residue (sodium acetate solution)mass of residue is thus 24 GRAMS. |
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