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16. Percentage composition of hydrogen in ethane isAno |
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Answer» The% w/wofHinC2H6 [ethane]is: % H= (MH,tot/MC2H6) ×100% where: MHis themolar mass of hydrogen,1.0079 g/mol, andMH,totis thetotalmass contributed by hydrogen in the compound. There are6equivalents of hydrogen in ethane, so we need to account for that. MC2H6is themolecular mass of ethane, which is the sum of the atomic masses of carbon and hydrogen. MC2H6=2×12.011+6×1.0079=30.069 g/mol Hence, the% w/wofHis: % H= 6×1.007930.069×100% =20.11% |
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