16. The electronic configuration of a dispositive metal inM is 2, 8, 1

1.	16. The electronic configuration of a dispositive metal inM is 2, 8, 14 and its atomic weight is 56 amu. Thenumber of ncutrons in its nuclcus would be(1) 30(2) 32(3) 34(4) 42
Answer» The correct answer is 30.It's atomic number=2+8+14=24No. of protons= 24+2=26rnSo now no. of neutrons = mass no. - no. of protons=56-26=30 but how can calculate number of protons please tell me immediately

16. The electronic configuration of a dispositive metal inM is 2, 8, 14 and its atomic weight is 56 amu. Thenumber of ncutrons in its nuclcus would be(1) 30(2) 32(3) 34(4) 42

Answer»

The correct answer is 30.It's atomic number=2+8+14=24No. of protons= 24+2=26rnSo now no. of neutrons = mass no. - no. of protons=56-26=30

but how can calculate number of protons please tell me immediately