1.

17. Prove - SecA (1- SinA ) (SecA +tanA) = 1.

Answer»

Seca(1-sina)(1/cosa+Sina/cosa)

=> seca(1-sina)(1-sina)/cosa

=> seca(1-sin²a)/cosa

=> seca cos ²a/cosa

=> 1/cos a×cosa

=1

Like my answer if you find it useful!



Discussion

No Comment Found