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18 a2 b2 c2 ÷ (- 6 abc) = ……………. A) – 3ab B) \(\frac{-ab}{c}\)C) abc2 D) ab |
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Answer» Correct option is A) – 3ab Correct option is (A) –3ab \(18\,a^2b^2c\div(-6\,abc)=\frac{18\,a^2b^2c}{-6\,abc}\) \(=\frac{6abc\times3ab}{-6\,abc}\) = -3ab |
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