18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ………….

18 g of glucose is dissolved in 90 g of water. The relative lowering o

1.	18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ………….
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`0.1 ` <br/> `(P^(@) -P)/(P ^(@)) = x _(2) impliesx_(2) =` No. of moles of <a href="https://interviewquestions.tuteehub.com/tag/glucose-1008493" style="font-weight:bold;" target="_blank" title="Click to know more about GLUCOSE">GLUCOSE</a> `= (18)/(<a href="https://interviewquestions.tuteehub.com/tag/180-279527" style="font-weight:bold;" target="_blank" title="Click to know more about 180">180</a>) =0.1` <br/> `therefore (P^(@) -P)/(P^(@)) =0.1`</body></html>