1.

18.The taxi fare in a city is charged according to the rate stated as: for the first3 km distance, the fare is Rs 10 and for the subsequent distance is Rs 4 perkm. Taking the distance covered as x Km and the total fare as Rs y, write alinear equation for the above and draw its graph From the graph find thedistance travelled when the amount paid is Rs 60.

Answer»

Taxi charges for the first km = Rs 20Taxi charges for the subsequent distance covered = Rs 12 per kmDistance covered = x kmgivengivenTotal fare = RsygivengivenFare charged for the distance covered leaving the first kilometre = Rs 12x−1x−1​So, taxi charge = 20 + 12x−1x−1But total fare = Rs ygivengiven∴ y = 20 + 12x - 12 = 12x + 8Hence, the required relation between x and y is y = 12x + 8For,x=0x=0⇒y=8⇒y=8For,x=3x=3⇒y=44⇒y=44Plot these pointsA(0,8),B(3,44)A(0,8),B(3,44)on the graph paper.Join them and extend in both the directions.Then,x=16x=16givesy=200y=200.So, for 16 km taxi charge = Rs 200.



Discussion

No Comment Found