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18.The taxi fare in a city is charged according to the rate stated as: for the first3 km distance, the fare is Rs 10 and for the subsequent distance is Rs 4 perkm. Taking the distance covered as x Km and the total fare as Rs y, write alinear equation for the above and draw its graph From the graph find thedistance travelled when the amount paid is Rs 60. |
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Answer» Taxi charges for the first km = Rs 20Taxi charges for the subsequent distance covered = Rs 12 per kmDistance covered = x kmgivengivenTotal fare = RsygivengivenFare charged for the distance covered leaving the first kilometre = Rs 12x−1x−1So, taxi charge = 20 + 12x−1x−1But total fare = Rs ygivengiven∴ y = 20 + 12x - 12 = 12x + 8Hence, the required relation between x and y is y = 12x + 8For,x=0x=0⇒y=8⇒y=8For,x=3x=3⇒y=44⇒y=44Plot these pointsA(0,8),B(3,44)A(0,8),B(3,44)on the graph paper.Join them and extend in both the directions.Then,x=16x=16givesy=200y=200.So, for 16 km taxi charge = Rs 200. |
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