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18. Water in an electric kettle connected to a220 V supply takes 5 minutes to reach its boilingpoint. How long will it take if the supply voltagefalls to 200 V ? |
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Answer» Answer: v....220v t....5m= 300s p=v SQUARE ×t /r of 1ST 220v supply p=v square × t / r of 2ND 200v supply by EQUATING both we get t X 200 ^2/r = t x 220^2/300 t = 300x220/200 t=336 s t = 6.05 minutes |
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