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18. Water in an electric kettle connected to a220 V supply takes 5 minutes to reach its boilingpoint. How long will it take if the supply voltagefalls to 200 V ?​

Answer»

Answer:

v....220v

t....5m= 300s

p=v SQUARE ×t /r of 1ST 220v supply

p=v square × t / r of 2ND 200v supply

by EQUATING both we get

t X 200 ^2/r = t x 220^2/300

t = 300x220/200

t=336 s

t = 6.05 minutes



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