180 g of glucose (C6H12O6) contains ……………. carbon atoms.(A)

1.	180 g of glucose (C6H12O6) contains ……………. carbon atoms.(A) 1.8 × 1023 (B) 1.8 × 1024(C) 3.6 × 1023(D) 3.6 × 1024
Answer» (D) \(3.6 × 10^{24}\) Number of moles of \(C_6H_{12}O_6=\frac{180}{180}=1\,\text{mole}\) \(\therefore\) one molecule of \(C_6H_{12}O_6\) contain = 6 carbon atoms. \(\therefore\) 1 mole of \(C_6H_{12}O_6\) molecule contain = \(6\times6.022\times10^{23}\) carbon atom = \(3.6\times10^{24}\) carbon atom. Option : (D) 3.6 × 10²⁴

180 g of glucose (C6H12O6) contains ……………. carbon atoms.(A) 1.8 × 1023 (B) 1.8 × 1024(C) 3.6 × 1023(D) 3.6 × 1024

Answer»

(D) \(3.6 × 10^{24}\)

Number of moles of \(C_6H_{12}O_6=\frac{180}{180}=1\,\text{mole}\)

\(\therefore\) one molecule of \(C_6H_{12}O_6\) contain = 6 carbon atoms.

\(\therefore\) 1 mole of \(C_6H_{12}O_6\) molecule contain = \(6\times6.022\times10^{23}\) carbon atom

= \(3.6\times10^{24}\) carbon atom.

Option : (D) 3.6 × 10²⁴