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180° What 15 DE JUis a1. In the figure, ABC is a triangle andpoint in it. OP and OQ are drawnperpendicular to the sides AB and BCrespectively. If ZB = 65 find ZPOQ13)805 |
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Answer» In given fig. POBQ is a quadrilateral We know sum of all angles of a quadrilateral is 360° Thus,65 + 90 + 90 + <POQ = 360<POQ = 360 - (180 + 65) = 360 - 245 = 115° |
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