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19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered?A. 100B. `6.02 xx 10^(23)`C. `6.02 xx 10^(24)`D. `6.02 xx 10^(25)`

Answer» Atoms recovered `=(19700)/(197)xxN_(A)`
`=100xx6.02xx10^(23)=6.02xx10^(23)`


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