·19. An open box at the top has its outer dimension 10 cm, 9 cm and 2

1.	·19. An open box at the top has its outer dimension 10 cm, 9 cm and 2.5 cm and its thickness is0.5 cm, find the volume of the metal used.
Answer» Outer dimensions = L = 10 cm, B = 9 cm and H = 2.5 cmOuter volume = L×B×H = 10 × 9 × 2.5 = 225 cu cm Thickness = 0.5 cm Inner dimensions =l = L - 2w = 10 - 2(0.5) = 9 cmb = B - 2w = 9 - 1 = 8 cmh = H - w = 2.5 - 0.5 = 2 cm (Open at the top) Inner volume = lbh = 9 × 8 × 2 = 144 cu cm Volume of metal = Outer volume - Inner volume = 225 - 144 = 81 cu cm I am understand questions

·19. An open box at the top has its outer dimension 10 cm, 9 cm and 2.5 cm and its thickness is0.5 cm, find the volume of the metal used.

Answer»

Outer dimensions = L = 10 cm, B = 9 cm and H = 2.5 cmOuter volume = L×B×H = 10 × 9 × 2.5 = 225 cu cm

Thickness = 0.5 cm

Inner dimensions =l = L - 2w = 10 - 2(0.5) = 9 cmb = B - 2w = 9 - 1 = 8 cmh = H - w = 2.5 - 0.5 = 2 cm (Open at the top)

Inner volume = lbh = 9 × 8 × 2 = 144 cu cm

Volume of metal = Outer volume - Inner volume = 225 - 144 = 81 cu cm

I am understand questions