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19. In ΔABC, Angle BAC = 90^°, AD is the bisector of angle BAC and DE is perpendicular to AC. Prove that - DE (AB+AC) = AB AC. |
| Answer» 19. In ΔABC, Angle BAC = 90^°, AD is the bisector of angle BAC and DE is perpendicular to AC. Prove that - DE (AB+AC) = AB AC. | |