1.

19. The ages of Leena and Heena are in the ratio 7:5. Ten years later, the ratio of their ages will be 9:7.Find their present ages.

Answer»

Let Leena's age be x and Heena's age be y.

x/y = 7/5

5x = 7y

5x - 7y = 0 . . . . . (1)

(x + 10)/(y + 10) = 9/7

7x + 70 = 9y + 90

7x - 9y = 20 . . . . . (2)

(1) × 7

35x - 49y = 0 . . . . . (3)

(2) × 5

35x - 45y = 100 . . . . . (4)

(3) - (4)

-4y = -100

y = 25

5x = 7 × 25

x = 35

Leena is 35 years and Heena is 25 years



Discussion

No Comment Found