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19 The molecular mass of compound is 1 80 and its percentage composition is C-40%11-6.66% and O-53.33% find empirical and moleculer formula.

Answer»

To find the ratio in moles you divide by theArof each element.Using approximate values:Ratio in gramsC:H:O⇒40:6.7:53.3Ratio in moles⇒4012:6.71:53.316⇒3.33:6.7:3.33Dividing through by3.33⇒1:2:1So the empirical formula is:CH2O


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