1cm'. If the same wire is bent in the formm a circular sheet of radius

1.	1cm'. If the same wire is bent in the formm a circular sheet of radius 14 cm, two circles of radius 3.5 em and8o squares of side 3 cm are removed as shown in the figure. Find thetwarea of the remaining sheet.Mental MATHS
Answer» R=14 cmtotal area= πr²=22/7196=616 cm²r2= 3.5 cmarea of the small circles= 2πr²=212.2522/7=77 cm²length of rectangle=3breadth=1area =lb=3 cm² area of the small circles+area of rectangle=77+3=80 cm² remaining area=616-80=536 cm² = Area of circular sheet = Pir^2 = 22/7 * 14^2 = 616 cm^2 = Area of the two circles = Pir^2 * 2 = 22/7 * 3.5^2 * 2 = 77 cm^2 = Area of the two squares = a^2 * 2 =3^2 * 2 = 18 cm^2 Total area of squares and circles = 77 + 18 = 95 cm^2. Area of remaining circular sheet = 616-95 = 521 cm^2. find the circumference of the circle whose diameter is 14 centimetre

1cm'. If the same wire is bent in the formm a circular sheet of radius 14 cm, two circles of radius 3.5 em and8o squares of side 3 cm are removed as shown in the figure. Find thetwarea of the remaining sheet.Mental MATHS

Answer»

R=14 cmtotal area= πr²=22/7*196=616 cm²r2= 3.5 cmarea of the small circles= 2*πr²=2*12.25*22/7=77 cm²length of rectangle=3breadth=1area =lb=3 cm²

area of the small circles+area of rectangle=77+3=80 cm²

remaining area=616-80=536 cm²

= Area of circular sheet = Pir^2 = 22/7 * 14^2 = 616 cm^2

= Area of the two circles = Pir^2 * 2 = 22/7 * 3.5^2 * 2 = 77 cm^2

= Area of the two squares = a^2 * 2 =3^2 * 2 = 18 cm^2

Total area of squares and circles = 77 + 18 = 95 cm^2.

Area of remaining circular sheet = 616-95 = 521 cm^2.

find the circumference of the circle whose diameter is 14 centimetre