1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). Select the correct statement. 1. The Fe^(3+) ions present in solution are reduced by Zn and H_(2)SO_(4) 2. H_(2) gas formed by the action of Zn and H_(2)SO_(4) is reducing agent. 3. Atomic form of H formed by the action of Zn and H_(2)SO_(4) is reducing agent 4. Nascent form of H formed by the action of Zn and H_(2)SO_(4) is reducing agent

1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate

1.	1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). Select the correct statement. 1. The Fe^(3+) ions present in solution are reduced by Zn and H_(2)SO_(4) 2. H_(2) gas formed by the action of Zn and H_(2)SO_(4) is reducing agent. 3. Atomic form of H formed by the action of Zn and H_(2)SO_(4) is reducing agent 4. Nascent form of H formed by the action of Zn and H_(2)SO_(4) is reducing agent
Answer» `1,2` `1,3` `1,4` `1,2,3` Solution :`Zn+H_(2)SO_(4)toZnSO_(4)+underset("Nascent H")(2H)` `FE^(3+)+HtoFe^(2+)+H^(+)`