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1In a single throw of a pair of different dice, what is the probability of getting(i) A prime number on each dice(i) A total of 9 or 11. |
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Answer» When we throw two die we have 6² i.e 36possiblity. So n(S) = 36i)Let the event A be having prime on each diceSo chances are {(2,2), (2,3), (2,5), (3,2), (3,3), (3,5), (5,2), (5,3), (5,5)}Hence n(A) = 9Thus P(A) = 9/36= 1/4ii) Let B be the event having the sum of 9 or 11So chances will be like {(3,6), (6.3), (4.5), (5,4), (5,6), (6,5)}So n(B) = 6Thus P(B) = 6/36 =1/6 |
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