1.

1rPr' + 3x +9-ohas two roots x =-1x=-2 and find q-p

Answer»

For x = - 1p*(-1)(-1) + 3(-1) +q = 0p - 3 + q = 0p + q = 3

For x=-2p*(-2)(-2)

Remaining solutionFor x = - 2p*(-2)(-2) + 3(-2) + q = 04p + q = 6

From first equationq = 3-p

4p + 3 - p = 63p = 3p = 1

q = 3-1 = 2

q-p = 2-1 = 1



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