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1rPr' + 3x +9-ohas two roots x =-1x=-2 and find q-p |
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Answer» For x = - 1p*(-1)(-1) + 3(-1) +q = 0p - 3 + q = 0p + q = 3 For x=-2p*(-2)(-2) Remaining solutionFor x = - 2p*(-2)(-2) + 3(-2) + q = 04p + q = 6 From first equationq = 3-p 4p + 3 - p = 63p = 3p = 1 q = 3-1 = 2 q-p = 2-1 = 1 |
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