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2.2 g of a compound of phosphorous and sulphurhas 1.24 g of 'P' in it. Its emperial formula is - |
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Answer» <P>Answer: The RATIO of weights of P:S is 1.24:[2.2−1.24] = 1.24:0.96. The MOLAR ratio is 31 1.24
: 32 0.96
=4:3. THEREFORE, the formula of the compound is P4S3
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