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(2/3) of a number is less than the original number by 20. Find the number. |
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Answer» Let the required number be x.Then, = (2x/3) = x – 20 Transposing x to LHS and it becomes –x. = (2x/3) – x = -20 = (2x – 3x)/3 = -20 = -x/3 = -20 Multiplying both side by – 3 = (-x/3) × -3 = -20 × -3 = x = 60 ∴ The required number is 60 |
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