2.56g of Sulphur is dissolved in 100g of carbon disulphide. The solution boils at 319.692 K. What is the molecular formula of Sulphur in solution? The boiling point of CS _(2) is 319.450K. Given that K _(b)for CS_(2) = 2.42K kg mol ^(-1)

2.56g of Sulphur is dissolved in 100g of carbon disulphide. The soluti

1.	2.56g of Sulphur is dissolved in 100g of carbon disulphide. The solution boils at 319.692 K. What is the molecular formula of Sulphur in solution? The boiling point of CS _(2) is 319.450K. Given that K _(b)for CS_(2) = 2.42K kg mol ^(-1)
Answer» Solution :`W_(2)=2.56g` `W_(1)=100 G` ` T = 319.692K` `K _(b) = 2.42 K kg mol ^(-1)` `Delta T_(b) = (319.692-319.450) K = 0.242 K` `M _(2) = (K_(b)xx W_(2) xx 1000)/(Delta T _(b)xx W_(1))= (2.42 xx2.56 xx 1000)/(0.242 xx 100)` `M _(2) = 256 g mol ^(-1)` MOLECULAR mass of SULPHUR in solution `= 256 g mol ^(-1)` Atomic mass of one mole of sulphur atom = 32 No. of atoms in a molecule of sulphur `= (256)/(32) =8` HENCE, molecular formula of sulphure is `S_(8),`