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2.56g of Sulphur is dissolved in 100g of carbon disulphide. The solution boils at 319.692 K. What is the molecular formula of Sulphur in solution? The boiling point of CS _(2) is 319.450K. Given that K _(b)for CS_(2) = 2.42K kg mol ^(-1)

Answer» <html><body><p></p>Solution :`W_(2)=2.56g` <br/> `W_(1)=100 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>` <br/> ` T = 319.692K` <br/> `K _(b) = 2.42 K kg mol ^(-1)` <br/> `Delta T_(b) = (319.692-319.450) K = 0.242 K` <br/> `M _(2) = (K_(b)xx W_(2) xx 1000)/(Delta T _(b)xx W_(1))= (2.42 xx2.56 xx 1000)/(0.242 xx 100)` <br/> `M _(2) = 256 g mol ^(-1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> mass of <a href="https://interviewquestions.tuteehub.com/tag/sulphur-1234343" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHUR">SULPHUR</a> in solution `= 256 g mol ^(-1)` <br/> Atomic mass of one mole of sulphur atom = <a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> <br/> No. of atoms in a molecule of sulphur `= (256)/(32) =8` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, molecular formula of sulphure is `S_(8),`</body></html>


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