2.665 g of a complex with molecular formula CrCl_(3).6 H_(2)O was dissolved in water. The solution was passed through a cation exchanger such that all ionizable Cl^(-) ions passed into the solution. The solution was collected and treated with AgNO_(3) solution. The precipitate of AgCl was filtered, dried and weighed. Its mass found to be 2.87 g. Find out the structural formula of the complex and name it on IUPAC system (Atomic mass : Cr = 52, Ag = 108, Cl = 35.5, N = 14).

2.665 g of a complex with molecular formula CrCl_(3).6 H_(2)O was diss

1.	2.665 g of a complex with molecular formula CrCl_(3).6 H_(2)O was dissolved in water. The solution was passed through a cation exchanger such that all ionizable Cl^(-) ions passed into the solution. The solution was collected and treated with AgNO_(3) solution. The precipitate of AgCl was filtered, dried and weighed. Its mass found to be 2.87 g. Find out the structural formula of the complex and name it on IUPAC system (Atomic mass : Cr = 52, Ag = 108, Cl = 35.5, N = 14).
Answer» Solution :Molar mass of the complex `CrCl_(3).6 H_(2)O=52+106.5+108=266.5 g mol^(-1)` `therefore` 2.665 g of the complex (i.e., complex reacted) = `(2.665)/(266.5)=0.01` MOLE Molar mass of AgCl = 108+35.5=143.5 g `mol^(-1)` `therefore` 2.87 g of AgCl (i.e., AgCl formed) = `(2.87)/(143.5)=0.02` mole Thus, 0.01 mole of the complex contained ionizable `Cl^(-)`=0.02 mole `therefore` 1 mole of the complex contained ionizable `Cl^(-)=(0.02)/(0.01)=2` mole This MEANS that in 1 molecule of the complex, there are `2 Cl^(-)` ions outside the coordination sphere. Remembering that coordination number of Cr is 6, the structural FORMULA of the complex will be `underset("Pentaaquachloridochromium (III) chloride monohydrate")([Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O)`