2.9 g of a gas at 95°C occupied the same volume as 0.184 g of dihydro

1.	2.9 g of a gas at 95°C occupied the same volume as 0.184 g of dihydrogen at 17°C, at the same pressure. What is the molar mass of the gas?
Answer» pV = {2.9 g}/{M} x R x 368 K Also pV = {0.184 g}/{2 g/mol} x R x 290 K From these equations, we can write {2.9 g}/{M} x R x 368 K = {0.184 g}/{2 g/mol} x R x 290 K or, M = {2.9 g x 2 g/mol x R x 368 K}/{0.184 g x R x 290 K} = 40 g/mol

2.9 g of a gas at 95°C occupied the same volume as 0.184 g of dihydrogen at 17°C, at the same pressure. What is the molar mass of the gas?

Answer»

pV = {2.9 g}/{M} x R x 368 K

Also pV = {0.184 g}/{2 g/mol} x R x 290 K

From these equations, we can write

{2.9 g}/{M} x R x 368 K = {0.184 g}/{2 g/mol} x R x 290 K

or, M = {2.9 g x 2 g/mol x R x 368 K}/{0.184 g x R x 290 K}

= 40 g/mol