1.

(2) A tent is in the form of a cylinder whose height is 5 m surmounted by a cone of equualbase. The diameter of base is 105 m. The slant height of cone is 60 m. Find the costcloth at R 15 per sq metre to make the tent.of

Answer»

Cylinder

h = 5m

Cone

d = 105m

r = 105/2

l = 50m

r of cone = r of cylinder

To find : CSA of the tent + cost

CSA of tent = CSA of cylinfer + CSA of cone

Proof : CSA of cylinder =2πrh22×15×51650m²

CSA of cone = πrl=8250m²Total area = 1650+8250 = 9900m²Cost = 9900×15 =148500 rupees

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